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Merge pull request #26 from nagadomi/py38

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Fix time.clock() error in Python 3.8
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SavMartin 2020-07-02 19:02:50 +01:00 committed by GitHub
commit 53d1f1bf5d
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1 changed files with 9 additions and 4 deletions
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13
op_rectify.py
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@ -4,6 +4,7 @@ import operator
from mathutils import Vector
from collections import defaultdict
from math import pi
import sys
import time
from math import radians, hypot
@ -38,7 +39,11 @@ class op(bpy.types.Operator):
rectify(self, context)
return {'FINISHED'}
def time_clock():
if sys.version_info >= (3, 3):
return time.process_time()
else:
return time.clock()
precision = 3
@ -61,7 +66,7 @@ def rectify(self, context):
def main(square = False, snapToClosest = False):
startTime = time.clock()
startTime = time_clock()
obj = bpy.context.active_object
me = obj.data
bm = bmesh.from_edit_mesh(me)
@ -310,7 +315,7 @@ def SuccessFinished(me, startTime):
#use for backtrack of steps
#bpy.ops.ed.undo_push()
bmesh.update_edit_mesh(me)
#elapsed = round(time.clock()-startTime, 2)
#elapsed = round(time_clock()-startTime, 2)
#if (elapsed >= 0.05): operator.report({'INFO'}, "UvSquares finished, elapsed:", elapsed, "s.")
return
@ -634,4 +639,4 @@ def hypotVert(v1, v2):
hyp = hypot(v1.x - v2.x, v1.y - v2.y)
return hyp
bpy.utils.register_class(op)
bpy.utils.register_class(op)